Because of the way the print class is implemented you will now have to cast the value to
have it treated as a character if you pass it an int.
There are two options. (both work in either pre 1.0 or 1.0)
Either cast the argument like this:
for (int i=47; i<127; i++) // send 80 consecutive displayable characters to the LCD
{
lcd.print((char) i);
delay(100); // this delay allows you to observe the addressing sequence
}
Or don't declare i as an int but a char instead.
for (char i=47; i<127; i++) // send 80 consecutive displayable characters to the LCD
{
lcd.print(i);
delay(100); // this delay allows you to observe the addressing sequence
}
If the argument to print() is an "int" then the print class assumes you want
to see the int value and will convert it to the ascii characters that represent the decimal
value rather than outputting the character value of the integer.
--- bill